(6k+7)(k-1)=0

Solution for (6k+7)(k-1)=0 equation:

(6k+7)(k-1)=0

We multiply parentheses ..

(+6k^2-6k+7k-7)=0

We get rid of parentheses

6k^2-6k+7k-7=0

We add all the numbers together, and all the variables

6k^2+k-7=0

a = 6; b = 1; c = -7;
Δ = b2-4ac
Δ = 12-4·6·(-7)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-13}{2*6}=\frac{-14}{12}
=-1+1/6
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+13}{2*6}=\frac{12}{12}
=1
$