4(4m-3)+(m-5)=-52

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Solution for 4(4m-3)+(m-5)=-52 equation: 



4(4m-3)+(m-5)=-52

We move all terms to the left:

4(4m-3)+(m-5)-(-52)=0

We add all the numbers together, and all the variables

4(4m-3)+(m-5)+52=0

We multiply parentheses

16m+(m-5)-12+52=0

We get rid of parentheses

16m+m-5-12+52=0

We add all the numbers together, and all the variables

17m+35=0

We move all terms containing m to the left, all other terms to the right

17m=-35

m=-35/17

m=-2+1/17

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