1/3(3j+5)=6-2j+4

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Solution for 1/3(3j+5)=6-2j+4 equation: 



1/3(3j+5)=6-2j+4

We move all terms to the left:

1/3(3j+5)-(6-2j+4)=0



Domain of the equation: 3(3j+5)!=0

j∈R



We add all the numbers together, and all the variables

1/3(3j+5)-(-2j+10)=0

We get rid of parentheses

1/3(3j+5)+2j-10=0

We multiply all the terms by the denominator


2j*3(3j+5)-10*3(3j+5)+1=0

Wy multiply elements

6j^2(3-30j(3+1=0

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