4(4d+1)-9d=6(2-d)

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Solution for 4(4d+1)-9d=6(2-d) equation: 



4(4d+1)-9d=6(2-d)

We move all terms to the left:

4(4d+1)-9d-(6(2-d))=0

We add all the numbers together, and all the variables

4(4d+1)-9d-(6(-1d+2))=0

We add all the numbers together, and all the variables

-9d+4(4d+1)-(6(-1d+2))=0

We multiply parentheses

-9d+16d-(6(-1d+2))+4=0



We calculate terms in parentheses: -(6(-1d+2)), so:

6(-1d+2)

We multiply parentheses

-6d+12

Back to the equation:

-(-6d+12)



We add all the numbers together, and all the variables

7d-(-6d+12)+4=0

We get rid of parentheses

7d+6d-12+4=0

We add all the numbers together, and all the variables

13d-8=0

We move all terms containing d to the left, all other terms to the right

13d=8

d=8/13

d=8/13

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