4(4a+2)=-8(-8-a)

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Solution for 4(4a+2)=-8(-8-a) equation: 



4(4a+2)=-8(-8-a)

We move all terms to the left:

4(4a+2)-(-8(-8-a))=0

We add all the numbers together, and all the variables

4(4a+2)-(-8(-1a-8))=0

We multiply parentheses

16a-(-8(-1a-8))+8=0



We calculate terms in parentheses: -(-8(-1a-8)), so:

-8(-1a-8)

We multiply parentheses

8a+64

Back to the equation:

-(8a+64)



We get rid of parentheses

16a-8a-64+8=0

We add all the numbers together, and all the variables

8a-56=0

We move all terms containing a to the left, all other terms to the right

8a=56

a=56/8

a=7

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