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-0.02x^2+1.2x+0.605=0
a = -0.02; b = 1.2; c = +0.605;
Δ = b2-4ac
Δ = 1.22-4·(-0.02)·0.605
Δ = 1.4884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.2)-\sqrt{1.4884}}{2*-0.02}=\frac{-1.2-\sqrt{1.4884}}{-0.04} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.2)+\sqrt{1.4884}}{2*-0.02}=\frac{-1.2+\sqrt{1.4884}}{-0.04} $
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