4(3z+4)-3(2z-3)=61

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Solution for 4(3z+4)-3(2z-3)=61 equation: 



4(3z+4)-3(2z-3)=61

We move all terms to the left:

4(3z+4)-3(2z-3)-(61)=0

We multiply parentheses

12z-6z+16+9-61=0

We add all the numbers together, and all the variables

6z-36=0

We move all terms containing z to the left, all other terms to the right

6z=36

z=36/6

z=6

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