0.2(y+7)+12=3(y-1)

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Solution for 0.2(y+7)+12=3(y-1) equation: 



0.2(y+7)+12=3(y-1)

We move all terms to the left:

0.2(y+7)+12-(3(y-1))=0

We multiply parentheses

0.2y-(3(y-1))+1.4+12=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We add all the numbers together, and all the variables

0.2y-(3y-3)+13.4=0

We get rid of parentheses

0.2y-3y+3+13.4=0

We add all the numbers together, and all the variables

-2.8y+16.4=0

We move all terms containing y to the left, all other terms to the right

-2.8y=-16.4

y=-16.4/-2.8

y=5+1/1.1666666666667

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