4(3y-5)=5(2y-2)

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Solution for 4(3y-5)=5(2y-2) equation: 



4(3y-5)=5(2y-2)

We move all terms to the left:

4(3y-5)-(5(2y-2))=0

We multiply parentheses

12y-(5(2y-2))-20=0



We calculate terms in parentheses: -(5(2y-2)), so:

5(2y-2)

We multiply parentheses

10y-10

Back to the equation:

-(10y-10)



We get rid of parentheses

12y-10y+10-20=0

We add all the numbers together, and all the variables

2y-10=0

We move all terms containing y to the left, all other terms to the right

2y=10

y=10/2

y=5

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