7+3(5x-4)=6-5(2x+1)

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Solution for 7+3(5x-4)=6-5(2x+1) equation: 



7+3(5x-4)=6-5(2x+1)

We move all terms to the left:

7+3(5x-4)-(6-5(2x+1))=0

We multiply parentheses

15x-(6-5(2x+1))-12+7=0



We calculate terms in parentheses: -(6-5(2x+1)), so:

6-5(2x+1)

determiningTheFunctionDomain
-5(2x+1)+6

We multiply parentheses

-10x-5+6

We add all the numbers together, and all the variables

-10x+1

Back to the equation:

-(-10x+1)



We add all the numbers together, and all the variables

15x-(-10x+1)-5=0

We get rid of parentheses

15x+10x-1-5=0

We add all the numbers together, and all the variables

25x-6=0

We move all terms containing x to the left, all other terms to the right

25x=6

x=6/25

x=6/25

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