4(3y-4)=16

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Solution for 4(3y-4)=16 equation: 



4(3y-4)=16

We move all terms to the left:

4(3y-4)-(16)=0

We multiply parentheses

12y-16-16=0

We add all the numbers together, and all the variables

12y-32=0

We move all terms containing y to the left, all other terms to the right

12y=32

y=32/12

y=2+2/3

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