6(2y-3)=-28

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Solution for 6(2y-3)=-28 equation: 



6(2y-3)=-28

We move all terms to the left:

6(2y-3)-(-28)=0

We add all the numbers together, and all the variables

6(2y-3)+28=0

We multiply parentheses

12y-18+28=0

We add all the numbers together, and all the variables

12y+10=0

We move all terms containing y to the left, all other terms to the right

12y=-10

y=-10/12

y=-5/6

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