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4(3y-2)=-(5-9y)
We move all terms to the left:
4(3y-2)-(-(5-9y))=0
We add all the numbers together, and all the variables
4(3y-2)-(-(-9y+5))=0
We multiply parentheses
12y-(-(-9y+5))-8=0
We calculate terms in parentheses: -(-(-9y+5)), so:We get rid of parentheses
-(-9y+5)
We get rid of parentheses
9y-5
Back to the equation:
-(9y-5)
12y-9y+5-8=0
We add all the numbers together, and all the variables
3y-3=0
We move all terms containing y to the left, all other terms to the right
3y=3
y=3/3
y=1
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