-4(n+12)=3-(n-3)

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Solution for -4(n+12)=3-(n-3) equation: 



-4(n+12)=3-(n-3)

We move all terms to the left:

-4(n+12)-(3-(n-3))=0

We multiply parentheses

-4n-(3-(n-3))-48=0



We calculate terms in parentheses: -(3-(n-3)), so:

3-(n-3)

determiningTheFunctionDomain
-(n-3)+3

We get rid of parentheses

-n+3+3

We add all the numbers together, and all the variables

-1n+6

Back to the equation:

-(-1n+6)



We get rid of parentheses

-4n+1n-6-48=0

We add all the numbers together, and all the variables

-3n-54=0

We move all terms containing n to the left, all other terms to the right

-3n=54

n=54/-3

n=-18

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