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10x^2=360
We move all terms to the left:
10x^2-(360)=0
a = 10; b = 0; c = -360;
Δ = b2-4ac
Δ = 02-4·10·(-360)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*10}=\frac{-120}{20} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*10}=\frac{120}{20} =6 $
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