4(3y-1)=3(2y)=12

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Solution for 4(3y-1)=3(2y)=12 equation: 



4(3y-1)=3(2y)=12

We move all terms to the left:

4(3y-1)-(3(2y))=0

determiningTheFunctionDomain
4(3y-1)-32y=0

We add all the numbers together, and all the variables

-32y+4(3y-1)=0

We multiply parentheses

-32y+12y-4=0

We add all the numbers together, and all the variables

-20y-4=0

We move all terms containing y to the left, all other terms to the right

-20y=4

y=4/-20

y=-1/5

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