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0=3x^2-8x+5
We move all terms to the left:
0-(3x^2-8x+5)=0
We add all the numbers together, and all the variables
-(3x^2-8x+5)=0
We get rid of parentheses
-3x^2+8x-5=0
a = -3; b = 8; c = -5;
Δ = b2-4ac
Δ = 82-4·(-3)·(-5)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2}{2*-3}=\frac{-10}{-6} =1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2}{2*-3}=\frac{-6}{-6} =1 $
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