4(3y-1)-6=3(y+2)

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Solution for 4(3y-1)-6=3(y+2) equation:



4(3y-1)-6=3(y+2)
We move all terms to the left:
4(3y-1)-6-(3(y+2))=0
We multiply parentheses
12y-(3(y+2))-4-6=0
We calculate terms in parentheses: -(3(y+2)), so:
3(y+2)
We multiply parentheses
3y+6
Back to the equation:
-(3y+6)
We add all the numbers together, and all the variables
12y-(3y+6)-10=0
We get rid of parentheses
12y-3y-6-10=0
We add all the numbers together, and all the variables
9y-16=0
We move all terms containing y to the left, all other terms to the right
9y=16
y=16/9
y=1+7/9

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