(8/3x-2)=(3/x+4)

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Solution for (8/3x-2)=(3/x+4) equation: 



(8/3x-2)=(3/x+4)

We move all terms to the left:

(8/3x-2)-((3/x+4))=0



Domain of the equation: 3x-2)!=0

x∈R





Domain of the equation: x+4))!=0

x∈R



We get rid of parentheses

8/3x-((3/x+4))-2=0

We calculate fractions


8x/3x^2+(-((3*3x)/3x^2-2=0

We add all the numbers together, and all the variables

8x/3x^2+(-((+3*3x)/3x^2-2=0

We calculate fractions

We do not support expression: x^4

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