4(3y+y)=40

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Solution for 4(3y+y)=40 equation: 



4(3y+y)=40

We move all terms to the left:

4(3y+y)-(40)=0

We add all the numbers together, and all the variables

4(+4y)-40=0

We multiply parentheses

16y-40=0

We move all terms containing y to the left, all other terms to the right

16y=40

y=40/16

y=2+1/2

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