4(3y+5)=5(y-2)

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Solution for 4(3y+5)=5(y-2) equation: 



4(3y+5)=5(y-2)

We move all terms to the left:

4(3y+5)-(5(y-2))=0

We multiply parentheses

12y-(5(y-2))+20=0



We calculate terms in parentheses: -(5(y-2)), so:

5(y-2)

We multiply parentheses

5y-10

Back to the equation:

-(5y-10)



We get rid of parentheses

12y-5y+10+20=0

We add all the numbers together, and all the variables

7y+30=0

We move all terms containing y to the left, all other terms to the right

7y=-30

y=-30/7

y=-4+2/7

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