If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2+5x-4=0
a = 6; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·6·(-4)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-11}{2*6}=\frac{-16}{12} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+11}{2*6}=\frac{6}{12} =1/2 $
| -6v-12(v-9)=12(6v-6) | | X^2(x-7)+18(x-7)=0 | | 5z+1=99 | | -17x-20=-13×+120 | | -4(x+1)-12=10+16 | | 2p-3+p-4+1=p | | -2(4a-8)=0 | | 2p-3+p-4=p | | 2x=50=4x-20 | | 0.45x+0.20(280-x)=69.75 | | 3x+4x=124 | | 3(q-9)=27 | | -3(5+8x)+4=-7x+40 | | -5(2y-3)=-15 | | 3(x+2)-(x-3)=5 | | 1/9=-b/b-20 | | 10-m=5(2m+2) | | 5(3x-2)=16× | | 5(x+2)-2=8+4 | | 2(x+2)-9(6x-6)=12 | | (a*2)+(a+4)/(a-1)=14 | | 3t-(6+t)=t+2 | | x2+65=209 | | 6(a-1)-a=a-1-2(a+1) | | 2x+x^2+1=100 | | 3(1-r)=-6r-15 | | 32x+8x2=0 | | x=x+8=50 | | 9x/2=8-x/3 | | -7a-18=20-3a | | 9x+18=-6-3x | | 6/r+4=42/77 |