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4(3y+1)=5y-11
We move all terms to the left:
4(3y+1)-(5y-11)=0
We multiply parentheses
12y-(5y-11)+4=0
We get rid of parentheses
12y-5y+11+4=0
We add all the numbers together, and all the variables
7y+15=0
We move all terms containing y to the left, all other terms to the right
7y=-15
y=-15/7
y=-2+1/7
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