13(1-z)+9z=-3

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Solution for 13(1-z)+9z=-3 equation: 



13(1-z)+9z=-3

We move all terms to the left:

13(1-z)+9z-(-3)=0

We add all the numbers together, and all the variables

13(-1z+1)+9z-(-3)=0

We add all the numbers together, and all the variables

9z+13(-1z+1)+3=0

We multiply parentheses

9z-13z+13+3=0

We add all the numbers together, and all the variables

-4z+16=0

We move all terms containing z to the left, all other terms to the right

-4z=-16

z=-16/-4

z=+4

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