4x+(90-x)=(180-x)+10

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Solution for 4x+(90-x)=(180-x)+10 equation: 



4x+(90-x)=(180-x)+10

We move all terms to the left:

4x+(90-x)-((180-x)+10)=0

We add all the numbers together, and all the variables

4x+(-1x+90)-((-1x+180)+10)=0

We get rid of parentheses

4x-1x-((-1x+180)+10)+90=0



We calculate terms in parentheses: -((-1x+180)+10), so:

(-1x+180)+10

We get rid of parentheses

-1x+180+10

We add all the numbers together, and all the variables

-1x+190

Back to the equation:

-(-1x+190)



We add all the numbers together, and all the variables

3x-(-1x+190)+90=0

We get rid of parentheses

3x+1x-190+90=0

We add all the numbers together, and all the variables

4x-100=0

We move all terms containing x to the left, all other terms to the right

4x=100

x=100/4

x=25

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