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4(3x-5)-5=4(x-4)+15
We move all terms to the left:
4(3x-5)-5-(4(x-4)+15)=0
We multiply parentheses
12x-(4(x-4)+15)-20-5=0
We calculate terms in parentheses: -(4(x-4)+15), so:We add all the numbers together, and all the variables
4(x-4)+15
We multiply parentheses
4x-16+15
We add all the numbers together, and all the variables
4x-1
Back to the equation:
-(4x-1)
12x-(4x-1)-25=0
We get rid of parentheses
12x-4x+1-25=0
We add all the numbers together, and all the variables
8x-24=0
We move all terms containing x to the left, all other terms to the right
8x=24
x=24/8
x=3
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