1/7y-2=3

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Solution for 1/7y-2=3 equation: 



1/7y-2=3

We move all terms to the left:

1/7y-2-(3)=0



Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R



We add all the numbers together, and all the variables

1/7y-5=0

We multiply all the terms by the denominator


-5*7y+1=0

Wy multiply elements

-35y+1=0

We move all terms containing y to the left, all other terms to the right

-35y=-1

y=-1/-35

y=1/35

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