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4(3x-5)-10=3(x+1)+3
We move all terms to the left:
4(3x-5)-10-(3(x+1)+3)=0
We multiply parentheses
12x-(3(x+1)+3)-20-10=0
We calculate terms in parentheses: -(3(x+1)+3), so:We add all the numbers together, and all the variables
3(x+1)+3
We multiply parentheses
3x+3+3
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
12x-(3x+6)-30=0
We get rid of parentheses
12x-3x-6-30=0
We add all the numbers together, and all the variables
9x-36=0
We move all terms containing x to the left, all other terms to the right
9x=36
x=36/9
x=4
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