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(4x)(2x-18)=180
We move all terms to the left:
(4x)(2x-18)-(180)=0
We multiply parentheses
8x^2-72x-180=0
a = 8; b = -72; c = -180;
Δ = b2-4ac
Δ = -722-4·8·(-180)
Δ = 10944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10944}=\sqrt{576*19}=\sqrt{576}*\sqrt{19}=24\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-24\sqrt{19}}{2*8}=\frac{72-24\sqrt{19}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+24\sqrt{19}}{2*8}=\frac{72+24\sqrt{19}}{16} $
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