5(y+2)=2(2-2y)

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Solution for 5(y+2)=2(2-2y) equation: 



5(y+2)=2(2-2y)

We move all terms to the left:

5(y+2)-(2(2-2y))=0

We add all the numbers together, and all the variables

5(y+2)-(2(-2y+2))=0

We multiply parentheses

5y-(2(-2y+2))+10=0



We calculate terms in parentheses: -(2(-2y+2)), so:

2(-2y+2)

We multiply parentheses

-4y+4

Back to the equation:

-(-4y+4)



We get rid of parentheses

5y+4y-4+10=0

We add all the numbers together, and all the variables

9y+6=0

We move all terms containing y to the left, all other terms to the right

9y=-6

y=-6/9

y=-2/3

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