4(3x-2)=7(x-2)

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Solution for 4(3x-2)=7(x-2) equation: 



4(3x-2)=7(x-2)

We move all terms to the left:

4(3x-2)-(7(x-2))=0

We multiply parentheses

12x-(7(x-2))-8=0



We calculate terms in parentheses: -(7(x-2)), so:

7(x-2)

We multiply parentheses

7x-14

Back to the equation:

-(7x-14)



We get rid of parentheses

12x-7x+14-8=0

We add all the numbers together, and all the variables

5x+6=0

We move all terms containing x to the left, all other terms to the right

5x=-6

x=-6/5

x=-1+1/5

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