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3(x+5)5x+7=0
We multiply parentheses
15x^2+75x+7=0
a = 15; b = 75; c = +7;
Δ = b2-4ac
Δ = 752-4·15·7
Δ = 5205
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-\sqrt{5205}}{2*15}=\frac{-75-\sqrt{5205}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+\sqrt{5205}}{2*15}=\frac{-75+\sqrt{5205}}{30} $
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