4(3x-2)=13+9(2x-1)

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Solution for 4(3x-2)=13+9(2x-1) equation: 



4(3x-2)=13+9(2x-1)

We move all terms to the left:

4(3x-2)-(13+9(2x-1))=0

We multiply parentheses

12x-(13+9(2x-1))-8=0



We calculate terms in parentheses: -(13+9(2x-1)), so:

13+9(2x-1)

determiningTheFunctionDomain
9(2x-1)+13

We multiply parentheses

18x-9+13

We add all the numbers together, and all the variables

18x+4

Back to the equation:

-(18x+4)



We get rid of parentheses

12x-18x-4-8=0

We add all the numbers together, and all the variables

-6x-12=0

We move all terms containing x to the left, all other terms to the right

-6x=12

x=12/-6

x=-2

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