4(2-x)-8x=7(1-x)

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Solution for 4(2-x)-8x=7(1-x) equation: 



4(2-x)-8x=7(1-x)

We move all terms to the left:

4(2-x)-8x-(7(1-x))=0

We add all the numbers together, and all the variables

4(-1x+2)-8x-(7(-1x+1))=0

We add all the numbers together, and all the variables

-8x+4(-1x+2)-(7(-1x+1))=0

We multiply parentheses

-8x-4x-(7(-1x+1))+8=0



We calculate terms in parentheses: -(7(-1x+1)), so:

7(-1x+1)

We multiply parentheses

-7x+7

Back to the equation:

-(-7x+7)



We add all the numbers together, and all the variables

-12x-(-7x+7)+8=0

We get rid of parentheses

-12x+7x-7+8=0

We add all the numbers together, and all the variables

-5x+1=0

We move all terms containing x to the left, all other terms to the right

-5x=-1

x=-1/-5

x=1/5

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