4(3x-2)-7=(4x-5)-22

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Solution for 4(3x-2)-7=(4x-5)-22 equation: 



4(3x-2)-7=(4x-5)-22

We move all terms to the left:

4(3x-2)-7-((4x-5)-22)=0

We multiply parentheses

12x-((4x-5)-22)-8-7=0



We calculate terms in parentheses: -((4x-5)-22), so:

(4x-5)-22

We get rid of parentheses

4x-5-22

We add all the numbers together, and all the variables

4x-27

Back to the equation:

-(4x-27)



We add all the numbers together, and all the variables

12x-(4x-27)-15=0

We get rid of parentheses

12x-4x+27-15=0

We add all the numbers together, and all the variables

8x+12=0

We move all terms containing x to the left, all other terms to the right

8x=-12

x=-12/8

x=-1+1/2

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