4(3x-2)+5=2(6x-4)+x

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Solution for 4(3x-2)+5=2(6x-4)+x equation: 



4(3x-2)+5=2(6x-4)+x

We move all terms to the left:

4(3x-2)+5-(2(6x-4)+x)=0

We multiply parentheses

12x-(2(6x-4)+x)-8+5=0



We calculate terms in parentheses: -(2(6x-4)+x), so:

2(6x-4)+x

We add all the numbers together, and all the variables

x+2(6x-4)

We multiply parentheses

x+12x-8

We add all the numbers together, and all the variables

13x-8

Back to the equation:

-(13x-8)



We add all the numbers together, and all the variables

12x-(13x-8)-3=0

We get rid of parentheses

12x-13x+8-3=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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