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5=(2y-3)/7
We move all terms to the left:
5-((2y-3)/7)=0
We multiply all the terms by the denominator
-((2y-3)+5*7)=0
We calculate terms in parentheses: -((2y-3)+5*7), so:We get rid of parentheses
(2y-3)+5*7
We add all the numbers together, and all the variables
(2y-3)+35
We get rid of parentheses
2y-3+35
We add all the numbers together, and all the variables
2y+32
Back to the equation:
-(2y+32)
-2y-32=0
We move all terms containing y to the left, all other terms to the right
-2y=32
y=32/-2
y=-16
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