4(3x-2)+1=6x-5

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Solution for 4(3x-2)+1=6x-5 equation: 



4(3x-2)+1=6x-5

We move all terms to the left:

4(3x-2)+1-(6x-5)=0

We multiply parentheses

12x-(6x-5)-8+1=0

We get rid of parentheses

12x-6x+5-8+1=0

We add all the numbers together, and all the variables

6x-2=0

We move all terms containing x to the left, all other terms to the right

6x=2

x=2/6

x=1/3

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