(5y-9)(6=y)=0

Solution for (5y-9)(6=y)=0 equation:

(5y-9)(6=y)=0

We move all terms to the left:

(5y-9)(6-(y))=0

We add all the numbers together, and all the variables

(5y-9)(-1y+6)=0

We multiply parentheses ..

(-5y^2+30y+9y-54)=0

We get rid of parentheses

-5y^2+30y+9y-54=0

We add all the numbers together, and all the variables

-5y^2+39y-54=0

a = -5; b = 39; c = -54;
Δ = b2-4ac
Δ = 392-4·(-5)·(-54)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-21}{2*-5}=\frac{-60}{-10}
=+6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+21}{2*-5}=\frac{-18}{-10}
=1+4/5
$