4(3x+8)+4x=7x+4(2x-13)+73

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Solution for 4(3x+8)+4x=7x+4(2x-13)+73 equation: 



4(3x+8)+4x=7x+4(2x-13)+73

We move all terms to the left:

4(3x+8)+4x-(7x+4(2x-13)+73)=0

We add all the numbers together, and all the variables

4x+4(3x+8)-(7x+4(2x-13)+73)=0

We multiply parentheses

4x+12x-(7x+4(2x-13)+73)+32=0



We calculate terms in parentheses: -(7x+4(2x-13)+73), so:

7x+4(2x-13)+73

We multiply parentheses

7x+8x-52+73

We add all the numbers together, and all the variables

15x+21

Back to the equation:

-(15x+21)



We add all the numbers together, and all the variables

16x-(15x+21)+32=0

We get rid of parentheses

16x-15x-21+32=0

We add all the numbers together, and all the variables

x+11=0

We move all terms containing x to the left, all other terms to the right

x=-11

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