3(2w+2)=4(4-w)

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Solution for 3(2w+2)=4(4-w) equation:



3(2w+2)=4(4-w)
We move all terms to the left:
3(2w+2)-(4(4-w))=0
We add all the numbers together, and all the variables
3(2w+2)-(4(-1w+4))=0
We multiply parentheses
6w-(4(-1w+4))+6=0
We calculate terms in parentheses: -(4(-1w+4)), so:
4(-1w+4)
We multiply parentheses
-4w+16
Back to the equation:
-(-4w+16)
We get rid of parentheses
6w+4w-16+6=0
We add all the numbers together, and all the variables
10w-10=0
We move all terms containing w to the left, all other terms to the right
10w=10
w=10/10
w=1

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