(1/p)+(2/p)+(3/p)=1

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Solution for (1/p)+(2/p)+(3/p)=1 equation: 



(1/p)+(2/p)+(3/p)=1

We move all terms to the left:

(1/p)+(2/p)+(3/p)-(1)=0



Domain of the equation: p)!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

(+1/p)+(+2/p)+(+3/p)-1=0

We get rid of parentheses

1/p+2/p+3/p-1=0

We multiply all the terms by the denominator


-1*p+1+2+3=0

We add all the numbers together, and all the variables

-1p+6=0

We move all terms containing p to the left, all other terms to the right

-p=-6

p=-6/-1

p=+6

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