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4(3x+5)=5(3x-5)-4x
We move all terms to the left:
4(3x+5)-(5(3x-5)-4x)=0
We multiply parentheses
12x-(5(3x-5)-4x)+20=0
We calculate terms in parentheses: -(5(3x-5)-4x), so:We get rid of parentheses
5(3x-5)-4x
We add all the numbers together, and all the variables
-4x+5(3x-5)
We multiply parentheses
-4x+15x-25
We add all the numbers together, and all the variables
11x-25
Back to the equation:
-(11x-25)
12x-11x+25+20=0
We add all the numbers together, and all the variables
x+45=0
We move all terms containing x to the left, all other terms to the right
x=-45
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