1/3(12x+9)=1/4(8+4x)

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Solution for 1/3(12x+9)=1/4(8+4x) equation: 



1/3(12x+9)=1/4(8+4x)

We move all terms to the left:

1/3(12x+9)-(1/4(8+4x))=0



Domain of the equation: 3(12x+9)!=0

x∈R





Domain of the equation: 4(8+4x))!=0

x∈R



We add all the numbers together, and all the variables

1/3(12x+9)-(1/4(4x+8))=0

We calculate fractions


(4x4/(3(12x+9)*4(4x+8)))+(-3x1/(3(12x+9)*4(4x+8)))=0



We calculate terms in parentheses: +(4x4/(3(12x+9)*4(4x+8))), so:

4x4/(3(12x+9)*4(4x+8))

We multiply all the terms by the denominator


4x4

We add all the numbers together, and all the variables

4x^4

We do not support expression: x^4

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