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4(3x+5)=19x+18-7x^2
We move all terms to the left:
4(3x+5)-(19x+18-7x^2)=0
We multiply parentheses
-(19x+18-7x^2)+12x+20=0
We get rid of parentheses
7x^2-19x+12x-18+20=0
We add all the numbers together, and all the variables
7x^2-7x+2=0
a = 7; b = -7; c = +2;
Δ = b2-4ac
Δ = -72-4·7·2
Δ = -7
Delta is less than zero, so there is no solution for the equation
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