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4(3x+3)=3(x-5)
We move all terms to the left:
4(3x+3)-(3(x-5))=0
We multiply parentheses
12x-(3(x-5))+12=0
We calculate terms in parentheses: -(3(x-5)), so:We get rid of parentheses
3(x-5)
We multiply parentheses
3x-15
Back to the equation:
-(3x-15)
12x-3x+15+12=0
We add all the numbers together, and all the variables
9x+27=0
We move all terms containing x to the left, all other terms to the right
9x=-27
x=-27/9
x=-3
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