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6=2/3(2x-1
We move all terms to the left:
6-(2/3(2x-1)=0
Domain of the equation: 3(2x-1)+6!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
3(2x-1)!=-6
x∈R
-(2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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