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4(3x+3)+12=16x+9-4x+15
We move all terms to the left:
4(3x+3)+12-(16x+9-4x+15)=0
We add all the numbers together, and all the variables
4(3x+3)-(12x+24)+12=0
We multiply parentheses
12x-(12x+24)+12+12=0
We get rid of parentheses
12x-12x-24+12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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