6+2(x-3)=3(x+4)

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Solution for 6+2(x-3)=3(x+4) equation: 



6+2(x-3)=3(x+4)

We move all terms to the left:

6+2(x-3)-(3(x+4))=0

We multiply parentheses

2x-(3(x+4))-6+6=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

2x-(3x+12)=0

We get rid of parentheses

2x-3x-12=0

We add all the numbers together, and all the variables

-1x-12=0

We move all terms containing x to the left, all other terms to the right

-x=12

x=12/-1

x=-12

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