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4(3x+2)=3(2x+1)
We move all terms to the left:
4(3x+2)-(3(2x+1))=0
We multiply parentheses
12x-(3(2x+1))+8=0
We calculate terms in parentheses: -(3(2x+1)), so:We get rid of parentheses
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
12x-6x-3+8=0
We add all the numbers together, and all the variables
6x+5=0
We move all terms containing x to the left, all other terms to the right
6x=-5
x=-5/6
x=-5/6
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